Gas at 15 ° C and a pressure of 760 mm Hg.Art. occupies a volume 2 liters. Bring the volume gas to normal conditions .

given:
P1 = 750 mm Hg.art.
Т1 = 150 = 15 + 273 = 288  
Т2 = 2730С
P2 = 760 mm Hg.art.
V1 = 2 lit
find:
V2 - ?
Solution:
On the basis of the combined Act defines volume V2
(P_1  •V_1)/T_1 =(P_2  •V_2)/T_2 ;
V_2=(P_1  •V_1  •〖 Т〗_2)/(T_1•Р_2 );
V_2=(750 mm Hg.art.  •2 lit •273°С)/(288 К•760 mm Hg.art..)=1,9 lit
Answer:  V2 = 1,9 lit.