(-4)+(-3)-(+7)=(-a)+(-7b)+1/3c=a+(2b-3c)=a-(2b+3c)=a+(b-(c-d)=a-((b-c)-d)=3a-(a+2b)=3m-(5m-(2m-1))= - вопрос №997990443771323233 от Sunrise01 03.05.2022 02:29

Question

Алгебра: (-4)+(-3)-(+7)=(-a)+(-7b)+1/3c=a+(2b-3c)=a-(2b+3c)=a+(b-(c-d)=a-((b-c)-d)=3a-(a+2b)=3m-(5m-(2m-1))= мне​

Sunrise01 · Answer

(-4)+(-3)-(+7)=-4-3-7=-14(-а)+(-7b)+1/3c= -a-7b+1/3c=-3ac-21bc+1/3ca+(2b-3c)=a+2b-3ca-(2b+3c)=a-2b-3ca+(b-(c-d)=b+c-da-((b-c)-d)=a-b+c+d3a-(a+2b)=2(a-b)3m-(5m-(2m-1))=3m-(5m-2m+1)=3m-(3m+1)=3m-3m-1=-1...

(-4)+(-3)-(+7)=(-a)+(-7b)+1/3c=a+(2b-3c)=a-(2b+3c)=a+(b-(c-d)=a-((b-c)-d)=3a-(a+2b)=3m-(5m-(2m-1))= мне​

(-4)+(-3)-(+7)=
(-a)+(-7b)+1/3c=
a+(2b-3c)=
a-(2b+3c)=
a+(b-(c-d)=
a-((b-c)-d)=
3a-(a+2b)=
3m-(5m-(2m-1))=

мне