1)sin (pi/2 + t)= -1/2 2)sin t=√3/2 решите

1)sin((π/2)+t)=cost

cost=-1/2

t= ± arccos(-1/2)+2πk, k∈  N

t= ± (π -arccos(1/2))+2πk, k∈  N

t=± (2π/3)+2πk, k∈  N

О т в е т. ± (2π/3)+2πk, k∈  N

2) sint=√3/2

t=(-1)ⁿarcsin(√3/2)+πn, n∈  N

t=(-1)ⁿ(π/3)+πn, n∈  N⇒t₁=(π/3)+2πm, m∈  N; t₂=(2π/3)+2πm, m∈  N

О т в е т. (-1)ⁿ(π/3)+πn, n∈  N