sin3x = √3/2; x∈[-3π/2; π].
3x = (-1)ⁿπ/3 + πn, n∈Z
x = (-1)ⁿπ/9 + πn/3, n∈Z
Промежутку [-3π/2; π] принадлежат корни: π/9; 2π/9; 7π/9; 8π/9; -4π/9; -5π/9; -10π/9; -11π/9.
sin3x = √3/2; x∈[-3π/2; π].
3x = (-1)ⁿπ/3 + πn, n∈Z
x = (-1)ⁿπ/9 + πn/3, n∈Z
Промежутку [-3π/2; π] принадлежат корни: π/9; 2π/9; 7π/9; 8π/9; -4π/9; -5π/9; -10π/9; -11π/9.