(x-1)²+(x+2)²-(x-1)(x+1)=14
x²-2x+1+x²+4x+4-x²+1-14=0
x²+2x-8=0
По теореме Виета:
x1 + x2= -b x1 + x2= -2
x1 × x2= c, x1 × x2= -8 => x1= 2; x2= -4
ответ: -4; 2
(x-1)²+(x+2)²-(x-1)(x+1)=14
x²-2x+1+x²+4x+4-x²+1-14=0
x²+2x-8=0
По теореме Виета:
x1 + x2= -b x1 + x2= -2
x1 × x2= c, x1 × x2= -8 => x1= 2; x2= -4
ответ: -4; 2
(x-1)²+(x+2)²-(x-1)(x+1)=14
x²-2x+1+x²+4x+4-x²+1-14=0
x²+2x-8=0
По теореме Виета:
x1 + x2= -b x1 + x2= -2
x1 × x2= c, x1 × x2= -8 => x1= 2; x2= -4
ответ: -4; 2