Решить (cos23°+ctg22°sin23°)/(ctg22°cos8°-sin8°) - вопрос №91883932322232288 от hudognik78 29.03.2021 15:37

Question

Алгебра: Решить (cos23°+ctg22°sin23°)/(ctg22°cos8°-sin8°)

hudognik78 · Answer

(Cos23°+cos22°/sin22 * sin23°)/(cos22°/sin 22 * cos8°-sin8°)=
( Cos23°*sin22 +cos22°*sin22 ):sin22 *(cos22*cos8 - sin22*sin8):(sin22 )=
sin(22+23)*cos(22+8)=sin45*cos30=√2:2*√3/2 =√6:4