1)√4/9× √1,96+ √9/25× √9,61 2)2× √4,41+ √49/100×0,7 - вопрос №9025837149196925961224414910007331024019445 от mashakostyuk8 21.04.2023 08:25

Question

Алгебра: 1)√4/9× √1,96+ √9/25× √9,61 2)2× √4,41+ √49/100×0,7 3)3× √10,24+0,1× √9/4 4) √5,76×4,2 √2/25+0,5678 5)2× √49+3 √81+2 √100 6)0,2 √0,0001+ √2,25-1,5

mashakostyuk8 · Answer

1)√4/9× √1,96+ √9/25× √9,612/3*√49/25+3/5*√691/1002/3*7/5+3/5*√691/10014/15+3√691/50 ≈ 2.512)2× √4,41+ √49/100×0,72√441/100+7/10*7/102*21/10+49/10021/5+49/100469/1004 69/100 или 4,693)3× √10,24+0,1× √9/43√256.25+1/10*3/23*16/5+3/2048/5+3/2039/4 9 3/4 или 9,754) √5,76×4,2 √2/25+0,5678√144/25*21/5*√2/5+2839/500012/5821/5*√2/5+2839/5000252√2/125+2839/5000 ≈ 3.415)2× √49+3 √81+2 √1002*7+3*9+2*1014+27+20 = 616)0,2 √0,0001+ √2,25-1,51/5*√1/10000+√√9/4-3/21/5*1/100+3/2-3/21/500+3/2-3/21/500 = 0,002...