1)2(x+3)(x+1)+8=(2x+1)(x+5) 2)5/x-2+2/x-4=11/(x-2)(x-4) - вопрос №892713912318215252241124313 от alinasolnishko21 12.04.2021 13:35

Question

Алгебра: 1)2(x+3)(x+1)+8=(2x+1)(x+5) 2)5/x-2+2/x-4=11/(x-2)(x-4) 3)корень x-1=x-3

alinasolnishko21 · Answer

1)2(x+3)(x+1)+8=(2x+1)(x+5)2(х² +4х +3) = 2х² +11х +52х² +8х +6 = 2х² +11х +5-3х = -1х = 1/32)5/(x-2) + 2/(x-4)=11/(x-2)(x-4) | *(х-2)(х-4)5(х -4) +2(х -2) = 115х -20 +2х -4 = 117х = 35х = 53) √(x-1) = x-3|²x - 1 = x² - 6x +96x = 10x = 10/6 = 5/3...