Решите плз все 3, 20 -(b-2)(b+2)-2(b+4)(b+2) (x-4)^2-2(x+1)(x+4) -10x-28> 8-6(2x+4)

- (b - 2)(b + 2) - 2(b + 4)(b + 2) = - (b² - 4) - 2(b² + 2b + 4b + 8) =
= - b² + 4 - 2b² - 12b - 16 = - 3b² - 12b - 12

(x - 4)² - 2(x + 1)(x + 4) = x² - 8x + 16 - 2(x² + 4x + x + 4) =
= x² - 8x + 16 - 2x² - 10x - 8 = - x² - 18x + 8

- 10x - 28 > 8 - 6(2x + 4)
- 10x - 28 > 8 - 12x - 24
- 10x + 12x > - 16 + 28
2x > 12
x > 6
x ∈ (6 ; + ∞)