4x(x-2)≤5; (2x+1)(x+1)≥3; 3x(1-x)≤-6; (1-2x)(1-3x)≤2 - вопрос №8232176425211331612132 от tamasha1993 20.06.2020 05:04

Question

Алгебра: 4x(x-2)≤5; (2x+1)(x+1)≥3; 3x(1-x)≤-6; (1-2x)(1-3x)≤2

tamasha1993 · Answer

4x^2 - 8x = 54x^2 - 8x - 5 = 04x^2 - 8x - 5 = 0D = 64+80=144 = 12^2x1 = (8+12)/8 = 2,5x2 = (8-12)/8 = -1/22x^2 + x + x + 1 = 32x^2 + 2x - 2 = 0x^2 + x - 1 = 0D = 1 + 4 = 5x1 = (-1 + sqrt5)/2x2 = (-1 - sqrt5)/2...