Решите систему уравнений сложения { 4x+3y=6,{2x+y=4;

  4x + 3y = 6                  4x + 3y = 6
                                   +
  2x + y = 4 I - 2             - 4x - 2y = - 8
                                  
                                             y = - 2
2x - 2 = 4
2x = 6
x = 3
ответ : (3 ; - 2)

{4х+3у=6,{2х+у=4;
{4х+3у=6,{у=4-2х;
{4х+3(4-2х)=6,{у=4-2х;
{4х+12-6х=6,{у=4-2х;
{-2х=-6;{у=4-2х;
{х=3,{у=4-2х;
{х=3,{у=4-(2*3);
{х=3,{у=4-6;
{х=3,{у=-2.
ответ: (3;-2)