(a+1/2а-2 + 6/2а²-2 - а+3/2а+3) * 4а²-4/3 = деление в столбик

1)(a+1)/2(a-1)+6/[2(a-1)(a+1)-(a+3)/2(a+1)=((a+1)²+6-(a+3)(a-1))/2(a²-1)=
=(a²+2a+1+6-a²+a-3a+3)/2(a²-1)=10/2(a²-1)=5/(a²-1)
2)5/(a²-1)*4(a²-1)/3=10/3=3 1/3