Решите систему уравнений {3xy=1 {6x+y=3

3xy = 1 
6x + y = 3 

y = 3 - 6x 
3x( 3 - 6x ) = 1 
9x - 18x² = 1 
18x² - 9x + 1 = 0 
D = 81 - 72 = 9 = 3²
x1 = ( 9 + 3 ) : 36 = 12/36 = 1/3 
x2 = ( 9 - 3 ) : 36 = 6/36 = 1/6 
y1 = 3 - 6*( 1/3 ) = 3 - 2 = 1 
y2 = 3 - 6*( 1/6 ) = 3 - 1 = 2 
ответ ( 1/3 ; 1 ) ; ( 1/6 ; 2 )