Решите уравнения: 1. cos²x-sin²x= -1 2. 2sinxcox=0 - вопрос №7173057112203163 от Kristina018191999 05.12.2022 23:21

Question

Алгебра: Решите уравнения: 1. cos²x-sin²x= -1 2. 2sinxcox=0 3. 1+cos6x=cos3x

Kristina018191999 · Answer

1) cos(x)^2 - sin(x)^2 = -11-sin(x)^2 - sin(x)^2 = -12sin(x)^2 = 2x = (-1)^n * p/2 + n*p2) 2cos(x)*sin(x) = 0, значит либо sin(x) = 0, либо cos(x) = 0sin(x) = 0  x = 0 + n*pcos(x) = 0  x = p/2 + n*p3) 1 + cos(6x) = cos(3x)1 + cos(3x)^2 - sin(3x)^2 - cos(3x) = 02cos(3x)^2 - cos(3x) = 02cos(3x)*(cos(3x)-1/2) = 0cos(3x) = 0  x = p/2 + n*pcos(3x) = 1/2  x = p/9 + n*p/3...