2sin^2x - 10cos2x = 9 sin2x + 10 решить уравнение

2sin²x - 10cos²x + 10sin²x = 18sinxcosx + 10
2sin²x - 10cos²x + 10sin²x - 10 - 18sinxcosx = 0
2sin²x - 10cos²x - 10cos²x - 18sinxcosx = 0
2sin²x - 18sinxcosx - 20cos²x = 0
Разделим на 2cos²x.
tg²x - 9tgx - 10 = 0
Пусть t = tgx.
t² - 9t - 10 = 0
t1 + t2 = 9
t1•t2 = -10

t1 = 10
t2 = -1
Обратная замена:
tgx = -1
x = -π/4 + πn, n ∈ Z

tgx = 10
x = arctg10 + πn, n ∈ Z.