Решите тригонометрическое уравнение cosx/4×sinπ/5-sinx/4×cosπ/5=√2/2 - вопрос №6530476454522 от Maowsk 21.11.2022 06:42

Question

Алгебра: Решите тригонометрическое уравнение cosx/4×sinπ/5-sinx/4×cosπ/5=√2/2

Maowsk · Answer

Sinxcosy-cosxsiny=sin(x-y)sin(π/5-x/4)=√2/2cos(π/5+x/4)=√2/2x/4+π/5=-π/4+2πn U x/4+π/5=π/4+2πnx/4=-π/4-π/5+2πn U x/4=π/4-π/5+2πnx/4=-9π/20+2πn U x/4=π/20+2πnx=-9π/5+8πn U x=π/5+8πn,n∈z...