[tex](x + 1)(x - 2) = 0 \ \ {17}^{3 } - {7}^{3} - вопрос №62785712017373213103 от vladzaorozhniy 24.04.2021 23:17

Question

Алгебра: [tex](x + 1)(x - 2) = 0 \ \ {17}^{3 } - {7}^{3} \ {21}^{3} + {10}^{3} \ ( - 2)( {3x}^{2} - 4x - 8) \ [/tex]​

vladzaorozhniy · Answer

Объяснение:(x+1)(x-2)=0       x+1=0       x₁=-1        x-2=0        x₂=2.17³-7³=(17-7)(17²+17*7+7²)=10*(289+119+49)=10*457=4570.21³+10³=(21+10)(21²-21*10+10²)=31*(441-210+100)=31*331=10261.(-2)*(3x²-4x-8)=16+8x-6x²....

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$(x + 1)(x - 2) = 0 \\ \\ {17}^{3 } - {7}^{3} \\ {21}^{3} + {10}^{3} \\ ( - 2)( {3x}^{2} - 4x - 8) \\$