Докажите тождество (9/(x+3)²+18/x²-9+9/(x-3)²)*(x/3-3/x)²=4 - вопрос №62379539318993334 от Khayalnuriev2005 11.02.2023 08:06

Question

Алгебра: Докажите тождество (9/(x+3)²+18/x²-9+9/(x-3)²)*(x/3-3/x)²=4

Khayalnuriev2005 · Answer

19/(x+3)²+18/(x-3)(x+3)+9/(x-3)²=(9x²-54x+81+18x²-162+9x²+54x+81)/(x²-9)²==36x²/(x²-9)²2)(x/3-3/x)²=(x²-9)²/9x²3)36x²/(x²-9)² *(x²-9)²/9x²=4...