Решите ради христа ((13,75+91/6)1,2))/((10,3-81/2)5/9)+((6,8-33/5)55/6)/((32/3-31/6)56)-27*1/6=

Ответ:

kato99

03.10.2020 22:11

((13,75+9*1/6)1,2))/((10,3-8*1/2)5/9)= $\frac{( \frac{1375}{100}+9*\frac{1}{6}* \frac{12}{10})}{ (\frac{103}{10}-8* \frac{1}{2}* \frac{5}{9} ) }= \frac{ \frac{1375}{100} + \frac{9*1}{6}*\frac{12}{10}}{\frac{103}{10}-\frac{8*1}{2}*\frac{5}{9}}=\frac{ \frac{1375}{100}+\frac{9}{6}*\frac{12}{10}}{\frac{103}{10}-\frac{8}{2}*\frac{5}{9}} =\frac{\frac{1375}{100}+\frac{9*12}{6*10}}{\frac{103}{10}-\frac{8*5}{2*9}}=\frac{\frac{1375}{100}+\frac{108}{60}}{\frac{103}{10}+\frac{40}{18}}=\frac{ \frac{1375*3}{100*3}+ \frac{108*5}{60*5} }{ \frac{103*9}{10*9}- \frac{40*5}{18*5}}= \frac{ \frac{4125+540}{300} }{ \frac{927-200}{90}}= \frac{ \frac{4665}{300}}{ \frac{727}{90}}= \frac{4665*90}{300*727}= \frac{419850}{218100}= \frac{2799*150}{1454*150}= \frac{2799}{1454}=$ $=1 \frac{1345}{1454}$
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((6,8-3*3/5)5*5/6)/((3*2/3-3*1/6)56)= $\frac{ \frac{68}{10}- \frac{9}{5}*5* \frac{5}{6}}{ (\frac{6}{3}- \frac{3}{6})*56}=\frac{ \frac{68}{10}- \frac{9*2}{5*2}*5* \frac{5}{6}}{ (\frac{6*2}{3*2}- \frac{3}{6})*56}=\frac{ \frac{68}{10}- \frac{18}{10}*5* \frac{5}{6}}{ (\frac{12}{6}- \frac{3}{6})*56}=\frac{ \frac{50}{10}*5* \frac{5}{6}}{\frac{9}{6}*56}=\frac{ \frac{1250}{60}}{\frac{504}{6}}=\frac{1250*6}{60*504}=\frac{7500}{30240}=\frac{125}{504}$

$1\frac{1345}{1454}+\frac{125}{504}-27*\frac{1}{6}=\frac{1*1345}{1454}+\frac{125}{504}-\frac{27*1}{6}= \frac{1345}{1454}+\frac{125}{504}-\frac{27}{6}=\frac{1345*252}{1454*252}$ $+\frac{125*727}{504*727}-\frac{27}{6}= \frac{338940}{366408}+ \frac{90875}{366408}-\frac{27}{6}= \frac{429815}{366408}-\frac{27}{6}=\frac{27*61068}{6*61068}=$ $\frac{429815}{366408}- \frac{1648836}{366408}=- \frac{1219021}{366408}=-3 \frac{119797}{366408}=-3,3269497....$