(4+1)(4^2+1)(4^4+1)(4^8+1)-1/3*4^16 распишите, - вопрос №5824472414214414811341613 от mytaevafati 03.01.2021 14:01

Question

Алгебра: (4+1)(4^2+1)(4^4+1)(4^8+1)-1/3*4^16 распишите, . ответ: -1/3

mytaevafati · Answer

(4+1)(4^2+1)(4^4+1)(4^8+1) = (4-1)(4+1)(4^2+1)(4^4+1)(4^8+1)/(4-1) = (4^2-1)(4^2+1)(4^4+1)(4^8+1)/3=(4^4-1)(4^4+1)(4^8+1)/3=(4^8-1)(4^8+1)/3=(4^16-1)/3.
(4^16-1)/3-1/3*4^16=4^16 / 3 - 1/3 - 4^16 / 3 = -1/3.