2sin^2 x+sin x-1=0 3cos^2 x-sin x+1=0 - вопрос №556689422103210 от makoldinvyacheoxyw3a 01.10.2022 17:11

Question

Алгебра: 2sin^2 x+sin x-1=0 3cos^2 x-sin x+1=0

makoldinvyacheoxyw3a · Answer

12sin²x+sinx-1=0sinx=a2a²+a-1=0D=1+8=9a1=(-1-3)/4=-1⇒sinx=-1⇒x=-π/2+2πn,n∈za2=(-1+3)/4=1/2⇒sinx=1/2⇒x=(-1)^k*π/6+πk,k∈z23cos²x-sinx+1=03-3sin²x-sinx+1=0sinx=a3a²+a-4=0D=1+48=49a1=(-1+7)/6=1⇒sinx=1⇒x=π/2+2πn,n∈za2=(-1-7)/6=-4/3⇒sinx=-4/3 -1 нет решения...