Много ! решите уравнения: 1)x(x-1)(x+5)=(x+3)^2(x-2) - вопрос №556599711532224233641 от alexeikomarow 17.11.2020 15:35

Question

Алгебра: Много ! решите уравнения: 1)x(x-1)(x+5)=(x+3)^2(x-2) 2)(x-4)^2=x(x-3) 3)6-4(x+1)=3x !

alexeikomarow · Answer

X(X - 1 )(X + 5 ) = (X + 3 )^2 *( X - 2 )
( X^2 - X )*( X + 5 ) = ( X - 2 )*( X^2 + 6X + 9 )
X^3 + 5X^2 - X^2 - 5X = X^3 + 6X^2 + 9X - 2X^2 - 12X - 18
X^3 + 4X^2 - 5X = X^3 + 4X^2 - 3X - 18
- 5X = - 3X - 18
- 2X = - 18
X = 9

( X - 4 )^2 = X*(X - 3 )
X^2 - 8X + 16 = X^2 - 3X
- 8X + 16 = - 3X
- 5X = - 16
X = 3,2

6 - 4*( X + 1 ) = 3X
6 - 4X - 4 = 3X
2 - 4X = 3X
7X = 2
X = 2/7