40 вычислите: 1) 16*2^-7 2) 25^-5^5^-9 3) 36^-3*(1/6)^-7 - вопрос №551662140116272255593363167 от danilmuratov20p02c8m 14.01.2020 11:33

Question

Алгебра: 40 вычислите: 1) 16*2^-7 2) 25^-5^5^-9 3) 36^-3*(1/6)^-7

danilmuratov20p02c8m · Answer

1) 16 * 2^(-7) = 2^4 * 2^(-7) = 2^(4 - 7) = 2^(-3) = 1/8
2) ((25^(-5))^5)^(-9) = (5^2)^(-5 * 5 * (-9)) = 5^2 * 225 = 5^450
3) 36^(-3) * (1/6) ^ (-7) = (6^2)^(-3) * 6^7 = 6^(-6) * 6^7 =
= 6^(-6 + 7) = 6^1 = 6