Решите уравнение б)4y^3-y=0 в)x^4-x^2=0 г)9y^2-4y^4=0 - вопрос №523838743042092440 от Alisherjon1985 17.08.2020 02:42

Question

Алгебра: Решите уравнение б)4y^3-y=0 в)x^4-x^2=0 г)9y^2-4y^4=0

Alisherjon1985 · Answer

4y^3 - y =0y(4y^2 - 1) = 0y =04y^2 - 1 = 04y^2 = 1y^2 = 1/4y = 1/2y = - 1/2ответ: y1 = 0, y2 = 1/2, y3 = - 1/2.x^4 - x^2 = 0x^2(x^2 - 1)=0x^2 = 0x = 0x^2 - 1 = 0x^2 = 1x = 1x = - 1ответ: x1 = 0, x2 = 1, x3 = - 19y^2 - 4y^4 = 0y^2( 9 - 4y^2) = 0y^2 = 0y = 09 - 4y^2 = 0- 4y^2 = - 94y^2 = 9y^2 = 9/4y = 3/2y =- 3/2ответ: y 1 = 0, y2 = 3/2, y3 = - 3/2....