Решите неравенства с log 1.log_2(x^2-3x+2)< 1+log_2(x+2) (

{x²-3x+2>0 ⇒ x1+x2=3 U x1*x2=2  x1=1 U x2=2⇒x<1 U x>2
{x+2>0⇒x>-2
{x²-3x+2<2(x+2)⇒x²-5x-2<0
D=25+8=33
x1=(3-√33 U x2=(3+√33)/2
(3-√33)/2<x<(3+√33)/2
x∈(-2;(3-√33)/2) U (2;(3+√33)/2)