Решите (3m+4)(3m-+5)^2=-11 (6x+1)^2-(6x-1)^2=0 (4-5p)^2=(3-5p)^2-3 - вопрос №5002220343521161261204523523 от samsamokruxa 03.07.2020 11:34

Question

Алгебра: Решите (3m+4)(3m-+5)^2=-11 (6x+1)^2-(6x-1)^2=0 (4-5p)^2=(3-5p)^2-3

samsamokruxa · Answer

(3m+4)(3m-4)-(3m+5)^2=-11(3m)^2-4^2-(3m+5)^2=-119m^2-16-(9m^2+30m+25)=-119m^2-16-9m^2-30m-25=-11-30m-41=-11-30m=-11+41-30m=30m=30/(-30)m=-1.(6x+1)^2-(6x-1)^2=0((6x+1)-(6x-1))*((6x+1)+(6x-1))=0(6x+1-6x+1)*(6x+1+6x-1)=02*12x=024x=0x=0/(4-5p)^2=(3-5p)^2-3(4-5p)^2-(3-5p)^2=-3((4-5p)-(3-5p))*((4-5p)+(3-5p))=-3(4-5p-3+5p)*(4-5p+3-5p)=-31*(7-10p)=-37-10p=-3-10p=-3-7-10p=-10p=-10/(-10)p=1....