2sin x 1 корень из 2 cosx 1 sin( x-п/6) =-1/2 - вопрос №48034862121612 от ukrainanadegda 21.06.2020 13:32

Question

Алгебра: 2sin x 1 корень из 2 cosx 1 sin( x-п/6) =-1/2

ukrainanadegda · Answer

2sinx 1sinx 1/2π/6+2πn x (π-π/6)+2πn; n-π/6+2πn x 5π/6 +2πn; n-целоесosx 1/√2arccos(1/√2)+2πn x (2π-arccos(1/√2))+2πn; n-π/4+2πn x 7π/4 +2πn, n-celoesin(x-π/6) -1/2-π/6+2πk x-π/6 (π+π/6)+2πK, K--π/6+π/6+2πK X 7π/6+π/6+2πK, K-2πK X 4π/3+2πK, K-CELOE...

2sin x> 1 корень из 2 cosx < 1 sin( x-п/6)> =-1/2