1) log4(32)+log4(14)-log4(7) 2) log2(x√2+4)=3 - вопрос №47385114324144722243331353547496 от Aleks19102007 15.04.2022 10:37

Question

Алгебра: 1) log4(32)+log4(14)-log4(7) 2) log2(x√2+4)=3 3) log3(135)-log(35) 4) log7(49^6) 5) log2(7)/log16(49) 6) log9(100)*lg(3) решить

Aleks19102007 · Answer

1) log4(32)+log4(14)-log4(7)=log4(448/7)=log4(64)=3 2) log2(x√2+4)=3 log(x√2+4)=log(8) x√2+4=8 x=2√2 4) log7(49^6)=12 5) log2(7)/log16(49)=2...