6x²+x-1=0 x²-5x-1=0 2x²-5x+3=0 x²+3x+1=0 3x²+7x-6=0 - вопрос №407418261051025303103760 от lesta2 30.05.2020 19:31

Question

Алгебра: 6x²+x-1=0 x²-5x-1=0 2x²-5x+3=0 x²+3x+1=0 3x²+7x-6=0

lesta2 · Answer

1). 6x² + x - 1 = 0D = b² - 4ac D = 1 - 4 × 6 × ( - 1) =1 + 24 = √25 = 5x₁ = - 1 + 5/ 2×6= 4/12 = 1/3x₂ = - 1 - 5/2×6 = - 6/12 = - 1/22) x² - 5x - 1 = 0D = 25 - 4 × 1 × ( - 1) = 25 + 4 = 29x₁ = 5 + √29/2x² = 5 - √29/23) 2x² - 5x + 3 = 0D = 25 - 4 × 2 × 3 = 25 - 24 = √1x₁ = 5 + 1 / 4 = 6/4 = 3/2x₂ = 5 - 1 / 4 = 14) x² + 3x + 1 = 0D = 9 - 4 × 1 × 1 = 9 - 4 = √5x₁ = - 3 + √5 / 2x₂ = - 3 - √5/25) 3x² + 7x - 6 = 0D = 49 - 4 × 3  × ( - 6) = 49 + 72 = 121x₁ = - 7 + 11/ 6 = 4/6 = 2/3x₂ = - 7 - 11 / 6 =...