1) 1-2sin^2a+cos2a; 2) 1-cos2a/sin^2a; 3) 2cos2a*tga/1-tg^2a - вопрос №356636111222212232212 от zhikinemil26 21.02.2021 18:43

Question

Алгебра: 1) 1-2sin^2a+cos2a; 2) 1-cos2a/sin^2a; 3) 2cos2a*tga/1-tg^2a тожденство sina*cosa-tga/1-(sina+cosa)^2=1/2tg^2a

zhikinemil26 · Answer

1)=cos2a+cos2a=2cos2a2)=2sin²a/sin²a=23)=(sina*cos²a-sina)/cosa : (sin²a+cos²a-sin²a-2sinacosa-cos²a)==sina(cos²a-1)/cosa : (-2sinacosa)=-sin³a/cosa*1/(-2sinacosa)=sin²a/2cos²a==1/2*tg²a...