3log1/2^2x-2log2x< =5 решить неравенство

3log²(1/2)x+2log(1/2)x-5≤0
log(1/2)x=a
3a²+2a-5≤0
D=4+60=64
a1=(-2-8)/6=-5/3
a2=(-2+8)/6=1
-5/3≤a≤1
log(1/2)x≥-5/3⇒x≤∛32
log(1/2)x≤1⇒x≥1/2
x∈[1/2;2∛4]