5arcsim√3/2 4arcsin1/2-3arctg(-1/√3) - вопрос №3140100532412313 от Mornes 18.09.2020 09:47

Question

Алгебра: 5arcsim√3/2 4arcsin1/2-3arctg(-1/√3)

Mornes · Answer

5arcsin√3/2=5*π/3=5π/34arcsin1/2=4*π/6=2π/33arctg(-1/√3)=3*(-π/6)=-π/35arcsin√3/2+4arcsin1/2-3arctg(-1/√3)=5π/3+2π/3+π/3=8π/3cos(x-π/5)≤√2/2π/4+2πn≤x-π/5≤7π/4+2πn9π/20+2πn≤x≤39π/20+2πnx∈[9π/20+2πn;39π/20+2πn]...

5arcsim√3/2 4arcsin1/2-3arctg(-1/√3)"