1)4^2-log_4(5) 2)5^log_5(10)-2 3)2^2log_2(5)+log_2(3) - вопрос №2971784142452551023222523 от bearn2p0dqt1 08.02.2020 18:35

Question

Алгебра: 1)4^2-log_4(5) 2)5^log_5(10)-2 3)2^2log_2(5)+log_2(3)

bearn2p0dqt1 · Answer

1) 4^(2 - log4_5)= 4^2 * 4^(-log4_5) = 16*(4^log4_5)^-1=
=16* 4^(5)^-1= 15*1/5 = 16/5 = 3,2.
2)5^(log5_10 - 2) = 5^log5_10 * 5^(-2) = 10 - 1/25 = 10-0,04= 9,96.

3)2^(2log2_5+ log2_3) = 2^(2log2_5) * 2^(log2_3) = 2^(log2_25) * 3 = 25*3 = 75