X=㏒₅9+1/㏒₁/₃5 вычислить значения 5x если

Объяснение:

log 5 (9) + 1/log 1/3 (5)

1/log a (b) = log b (a)

log 5 (9) + log 5 (1/3)

log a (b) + log a (c) = log a (bc)

log 5 (9 * 1/3) = log 5 (3)

x=log 5 (3)

5x = 5 log 5 (3)

5x = log 5 (3^5)

5x = log 5 (243)