Tg a ? если cos a =1 / √10 a€[3π/2; 2π] 3cos - вопрос №24494261103223223322 от 31.03.2021 11:27

Question

Алгебра: Tg a ? если cos a =1 / √10 a€[3π/2; 2π] 3cos a ? если sin a =2√2/3 a€[3π/2; 2π]

 · Answer

[email protected][email protected]/[email protected]
[email protected]^[email protected]^2=1
[email protected]^[email protected]^2
[email protected]=sqrt([email protected]^2)=sqrt(1-1/100)=sqrt(99/100)=3√11/10
[email protected]=3√11/10*√10=3sqrt(11/10)