Разложите на множители квадратный трехчлен:
1)х2 – 11х + 24;
2)-x2 - 8x + 20;​

Объяснение:

1) x^2 - 11x + 24 = a(x - x1)(x - x2)

x^2 - 11x + 24 = 0

D = 121 - 96 = 25.

√D = √25 = 5

x1 = (11 - 5) / 2 = 3

x2 = (11 + 5) / 2 = 8

x^2 - 11x + 24 = (x - 3)(x - 8)

2) -x^2 - 8x + 20 = a(x - x1)(x - x2)

x^2 + 8x - 20 = 0

D = 64 + 80 = 144

√D = √144 = 12

x1 = (- 8 - 12) / 2 = -10

x2 = (-8 + 12) / 2 = 2

-x^2 - 8x + 20 = -(x + 10)(x - 2)