(x^2-6)/(x-3) = x/(x-3)
(x^2-6-x)/(x-3)=0
x2-x-6=0; х не= 3
d=1+24=25
x1=(1-5)/2=-2
x2=(1+5)/2=3
ответ: х=-2
(x^2-6)/(x-3) = x/(x-3)
(x^2-6-x)/(x-3)=0
x2-x-6=0; х не= 3
d=1+24=25
x1=(1-5)/2=-2
x2=(1+5)/2=3
ответ: х=-2