1+2㏒(3)2 / (1+㏒(3)2)^ + (㏒(6)2)^
вычислите

2log(1/3)6 - 1/2log(1/3)400 + 3log(1/3) ³√45 =

= log (1/3)6^2 - log(1/3)√(400) + log(1/3)(∛45)^3 =

= log(1/3) 36 - log (1/3) 20 + log(1/3) 45 =

= log (1/3) (36/20) + log (1/3) 45 =

= log (1/3) (9/5) + log (1/3) 45 =

= log (1/3) ((9*45)/5) =

= log (1/3) 81 =

= log 3^(-1) 3^4 =

= - log 3 3^4 = - 4

Объяснение:

если не ошибаюсь правильно