cos(3п/2-x/2)=sqr3/2
Преобразуем cos(3п/2-x/2).
cos(3п/2-x/2) = - sin(x/2)
sin(x/2) = - sqr3/2
x/2 = (-1)^K * arcsin(-sqr3/2) + п*k , k∈Z
x = (-1)^k * ( - 2 * п / 3) + 2*п*k, k∈Z
cos(3п/2-x/2)=sqr3/2
Преобразуем cos(3п/2-x/2).
cos(3п/2-x/2) = - sin(x/2)
sin(x/2) = - sqr3/2
x/2 = (-1)^K * arcsin(-sqr3/2) + п*k , k∈Z
x = (-1)^k * ( - 2 * п / 3) + 2*п*k, k∈Z