Решите уравнение: 1)sin x= √2/22)sin x= -√2/23)sin - вопрос №146205201222223324325 от tim2003np0acpp 24.08.2021 10:50

Question

Алгебра: Решите уравнение: 1)sin x= √2/22)sin x= -√2/23)sin x= - √3/24)sin x= √3/25)sin x= 4/5​

tim2003np0acpp · Answer

1) sin x = √2/2

x = (-1)ⁿ × arcsin √2/2 + πn, n∈Z

x = (-1)ⁿ × π/4 + πn, n∈Z

2) sin x = -√2/2

x = (-1)ⁿ × arcsin (-√2/2) + πn, n∈Z

x = (-1)ⁿ × -arcsin √2/2 + πn, n∈Z

x = (-1)ⁿ × (-π/4) + πn, n∈Z

3) sin x = -√3/2

x = (-1)ⁿ × arcsin (-√3/2) + πn, n∈Z

x = (-1)ⁿ × -arcsin √3/2 + πn, n∈Z

x = (-1)ⁿ × (-π/3) + πn, n∈Z

4) sin x = √3/2

x = (-1)ⁿ × arcsin √3/2 + πn, n∈Z

x = (-1)ⁿ × π/3 + πn, n∈Z

5) sin x = 4/5

x = (-1)ⁿ × arcsin 4/5 + πn, n∈Z

x = (-1)ⁿ × 0,927295 + πn, n∈Z

x = (-1)ⁿ × 53,1° + πn, n∈Z

Решите уравнение: 1)sin x= √2/22)sin x= -√2/23)sin x= - √3/24)sin x= √3/25)sin x= 4/5​