х^2 + 2у^2 ) 2 – (5х^2 + 2у^2 )(5х^2 – 2у^2) - вопрос №12569831222252225222 от maximb164mjqj 13.09.2022 14:05

Question

Алгебра: х^2 + 2у^2 ) 2 – (5х^2 + 2у^2 )(5х^2 – 2у^2)

maximb164mjqj · Answer

Первый

(5x² + 2y²)² - (5x² + 2y²)(5x² - 2y²) = (5x² + 2y²)(5x² + 2y² - 5x² + 2y²) =

= (5x² + 2y²) * 4y² = 20x²y² + 8y⁴

Второй

(5x² + 2y²)² - (5x² + 2y²)(5x² - 2y²) = 25x⁴ + 20x²y² + 4y⁴ - 25x⁴ + 4y⁴ =

= 20x²y² + 8y⁴