X+5 x 50 + = x-5 x+5 x^2-25 решить ур-е

x+5/x-5 + x/x+5= 50/ x^2-25

x+5/(x-5)(x+5) + x(X-5)(x+5) = 50/ (x-5)(x+5)

(x+5)^2+x(x-5)=50

x^2+10x+25+x^2-5x=50

2x^2+5x-25=0

D=25-200=-175<0

x^2+10*x+25+x*(x-5)=50, 2*x^2+5*x-25=0, D=25+200=225, x1=(-5-15)/4=-5, x2=(-5+15)/4=5/2.