Sin^x/2+sin^x+sin^5x/2+sin^2x=2
сроно

ответ:

(sin(+(sin(+(sin((5*x)+(sin(2*=2; (sin(=(1-cos(x))/2; (sin((5*x)=(1-cos(5*x))/2; (sin(=(1-cos(2*x))/2; (sin(2*=(1-cos(4*x))/2;  

cos(x)+cos(2*x)+cos(4*x)+cos(5*x)=0; 2*cos(3*x)*cos(2*x)+2*cos(3*x)*cos(x)=0;  

cos(3*x)*(cos(2*x)+cos(x))=0; cos(3*x1)=0; cos(2*x)+cos(x)=0; 2*cos(1,5*x)*cos(0,5*x)=0; cos(1,5*x2)=0; cos(0,5*x3)=0

объяснение: